Math Core

Module 4.3 · Geometry

Power of a point

Draw any line through a point PP that hits a circle twice, at AA and BB. Surprisingly, the product PA⋅PBPA \cdot PB is the same for every such line. That single fact, called the Power of a Point, unlocks a huge number of AMC circle problems involving chords, secants and tangents.

The three cases

Power of a Point

Let PP be a point and ω\omega a circle. For every line through PP meeting ω\omega at AA and BB, the product PA⋅PBPA \cdot PB is the same. So:

  • Two chords meeting inside at PP: PA⋅PB=PC⋅PDPA \cdot PB = PC \cdot PD.
  • Two secants from an outside point PP: PA⋅PB=PC⋅PDPA \cdot PB = PC \cdot PD, where A,CA, C are the near points and B,DB, D the far points.
  • A tangent and a secant from PP: PT2=PA⋅PBPT^2 = PA \cdot PB, where TT is the point of tangency.
Two chords crossing at P (the dot). The two pieces of one chord have the same product as the two pieces of the other.

Why it works. For two chords ABAB and CDCD crossing at PP, the inscribed angles ∠BAD\angle BAD and ∠BCD\angle BCD subtend the same arc, so they are equal, and the vertical angles at PP are equal. So △PAD∼△PCB\triangle PAD \sim \triangle PCB, which gives PAPC=PDPB\dfrac{PA}{PC} = \dfrac{PD}{PB}, or PA⋅PB=PC⋅PDPA \cdot PB = PC \cdot PD. The outside cases work the same way. A tangent is the limiting case of a secant whose two intersection points have merged into one.

The power as a number

Draw the line through PP and the center OO. It meets the circle at distances d−rd - r and d+rd + r from PP (where d=OPd = OP and rr is the radius). So the common product is

PA⋅PB=∣d2−r2∣.PA \cdot PB = |d^2 - r^2|.

This is the power of PP. It is positive outside the circle (equal to the tangent length squared), zero on the circle, and negative inside if you use signed lengths.

Worked example: Crossing chords

Chords ABAB and CDCD meet at PP. If AP=4AP = 4, PB=6PB = 6 and CP=3CP = 3, find PDPD.

3⋅PD=4⋅63 \cdot PD = 4 \cdot 6, so PD=8PD = 8.

Worked example: Tangent and secant

From a point PP outside a circle, a secant meets the circle at AA and BB with PA=4PA = 4 and AB=12AB = 12. Find the length of a tangent from PP.

PB=4+12=16PB = 4 + 12 = 16, so PT2=4⋅16=64PT^2 = 4 \cdot 16 = 64 and PT=8PT = 8.

Common mistake

In the secant cases, the lengths are measured from PP: use PA⋅PBPA \cdot PB where PBPB is the whole secant, not PA⋅ABPA \cdot AB. Convert "the chord has length 1212" into PB=PA+12PB = PA + 12 first.

Worked example: Finding a radius from a chord

A chord of a circle has length 2424. The arc it cuts off rises 88 above the chord at its midpoint. Find the radius.

Extend the perpendicular bisector of the chord to a full diameter. It crosses the chord at the midpoint MM and splits the diameter into pieces 88 and 2r−82r - 8. By crossing chords, 12⋅12=8(2r−8)12 \cdot 12 = 8(2r - 8), so 2r−8=182r - 8 = 18 and r=13r = 13.

Worked example: Using the distance to the center

Point PP is 33 units from the center of a circle of radius 55. Every chord through PP is split by PP into two pieces. What is the product of the pieces, and what is the shortest chord through PP?

The power is r2−d2=25−9=16r^2 - d^2 = 25 - 9 = 16, so every product is 1616. The shortest chord is perpendicular to OPOP, where the two pieces are equal: each is 44, so the chord has length 88.

Tip

Equal tangents. Two tangent segments from the same point to a circle have equal length. And if two circles meet at AA and BB, every point PP on line ABAB has the same power PA⋅PBPA \cdot PB with respect to both circles, so the tangents from PP to the two circles are equal. That line is called the radical axis.

Practice

Practice 1

Chords AB‾\overline{AB} and CD‾\overline{CD} of a circle meet at PP. If AP=6AP = 6, PB=8PB = 8 and CD=16CD = 16, what is ∣CP−PD∣|CP - PD|?

Enter a number. Fractions like 3/4 and sqrt(2) are OK.

Practice 2

From a point PP outside a circle, the tangent segment to the circle has length 1010. A line through PP meets the circle at AA and BB, with PA=5PA = 5. What is ABAB?

Practice 3

Point PP is 66 units from the center of a circle of radius 1010. What is the length of the shortest chord of the circle that passes through PP?

Enter a number. Fractions like 3/4 and sqrt(2) are OK.

Practice 4

A circular arch spans 3030 feet at its base (the chord) and rises 55 feet above the base at its highest point. What is the radius of the circle, in feet?

Practice 5

Circles ω1\omega_1 and ω2\omega_2 meet at points AA and BB. Point PP lies on line ABAB, outside both circles, with PA=4PA = 4 and PB=9PB = 9. What is the length of a tangent segment from PP to ω2\omega_2?

Enter a number. Fractions like 3/4 and sqrt(2) are OK.

Practice 6

From a point PP outside a circle, one line meets the circle at AA and BB with PA=3PA = 3 and AB=9AB = 9. A second line meets the circle at CC and DD (with CC between PP and DD) so that PC=CDPC = CD. What is PDPD?

Practice 7

A circle has center OO and radius 55. Point PP is 1313 units from OO. A line through PP meets the circle at AA and BB with AB=8AB = 8. What is PA+PBPA + PB?

Practice 8

Circles of radius 33 and 55 are externally tangent at point KK. A common external tangent line touches the circles at T1T_1 and T2T_2. The common tangent line through KK meets T1T2‾\overline{T_1T_2} at MM. What is MKMK?

Real contest practice

  • 2013 AMC 10A, Problem 23: a circle centered at a vertex cuts the opposite side; the power of a point gives an equation in integers.
  • 2012 AMC 12A, Problem 16: two circles where one passes through the other's center; the power of a point finds the radius.