Math Core

Lesson 7.6 · Exponents and Exponential Functions

Geometric sequences

In an arithmetic sequence you add the same number to get from one term to the next. In a geometric sequence you multiply by the same number instead. Geometric sequences are the step-by-step version of exponential functions, and they describe anything that repeatedly doubles, halves or grows by a fixed percent.

Common ratio

Look at the sequence 3,6,12,24,48,…3, 6, 12, 24, 48, \dots Each term is 22 times the term before it. Dividing any term by the previous one always gives 22:

63=126=2412=4824=2.\frac{6}{3} = \frac{12}{6} = \frac{24}{12} = \frac{48}{24} = 2.

Definition

Geometric sequence

A geometric sequence is a sequence in which each term after the first is found by multiplying the previous term by the same nonzero number rr, called the common ratio.

To find rr, divide any term by the term before it: r=anan−1r = \dfrac{a_{n}}{a_{n-1}}.

The ratio can be any nonzero number:

  • 5,15,45,135,…5, 15, 45, 135, \dots has r=3r = 3 (the terms grow).
  • 64,32,16,8,…64, 32, 16, 8, \dots has r=12r = \tfrac{1}{2} (the terms shrink toward 00).
  • 2,−6,18,−54,…2, -6, 18, -54, \dots has r=−3r = -3 (the signs alternate).

Arithmetic or geometric?

To classify a sequence, test both patterns:

sequencedifferencesratiostype
4,7,10,134, 7, 10, 133,3,33, 3, 374,107,1310\tfrac{7}{4}, \tfrac{10}{7}, \tfrac{13}{10}arithmetic
4,12,36,1084, 12, 36, 1088,24,728, 24, 723,3,33, 3, 3geometric
1,4,9,161, 4, 9, 163,5,73, 5, 74,94,1694, \tfrac{9}{4}, \tfrac{16}{9}neither

A constant difference means arithmetic; a constant ratio means geometric. Some sequences are neither.

A recursive rule

A recursive rule gives the first term and tells how to get each term from the one before it. For 3,6,12,24,…3, 6, 12, 24, \dots:

a1=3,an=2⋅an−1.a_1 = 3, \qquad a_n = 2 \cdot a_{n-1}.

Recursive rules are natural, but slow for far-off terms. To find a30a_{30} you'd have to compute all 2929 terms before it.

An explicit rule

Write the terms in a way that shows how many times you've multiplied by rr:

terma1a_1a2a_2a3a_3a4a_4ana_n
valuea1a_1a1ra_1 ra1r2a_1 r^2a1r3a_1 r^3a1rn−1a_1 r^{n-1}

To reach the nnth term, you multiply by rr one time fewer than the term number, because the first term uses no multiplications at all.

Formulas for a geometric sequence

With first term a1a_1 and common ratio rr:

recursive: a1 given,  an=r⋅an−1explicit: an=a1⋅r n−1\text{recursive: } a_1 \text{ given}, \ \ a_n = r \cdot a_{n-1} \qquad\qquad \text{explicit: } a_n = a_1 \cdot r^{\,n-1}

Common mistake

The exponent in the explicit rule is n−1n - 1, not nn. For 3,6,12,…3, 6, 12, \dots the formula an=3⋅2n−1a_n = 3 \cdot 2^{n-1} gives a1=3⋅20=3a_1 = 3 \cdot 2^0 = 3, which is correct. Using 3⋅2n3 \cdot 2^n would give a1=6a_1 = 6, which is the second term.

Worked example: Finding a far-off term

Find the 88th term of 5,15,45,135,…5, 15, 45, 135, \dots

The first term is a1=5a_1 = 5 and the ratio is r=155=3r = \dfrac{15}{5} = 3.

a8=5⋅38−1=5⋅37=5⋅2187=10,935.a_8 = 5 \cdot 3^{8-1} = 5 \cdot 3^7 = 5 \cdot 2187 = 10{,}935.

Worked example: A negative ratio

Write an explicit rule for 2,−6,18,−54,…2, -6, 18, -54, \dots and find a6a_6.

The ratio is r=−62=−3r = \dfrac{-6}{2} = -3, so an=2(−3)n−1a_n = 2(-3)^{n-1}. Then

a6=2(−3)5=2(−243)=−486.a_6 = 2(-3)^5 = 2(-243) = -486.

Put parentheses around a negative ratio. Without them, −35-3^5 would mean −(35)-(3^5), which happens to give the same value here but would be wrong for even exponents.

Connection to exponential functions

The explicit rule an=a1⋅rn−1a_n = a_1 \cdot r^{n-1} looks a lot like f(x)=a⋅bxf(x) = a \cdot b^x. A geometric sequence is an exponential function whose inputs are only the counting numbers 1,2,3,…1, 2, 3, \dots If you plot the terms, the points lie on an exponential curve.

The terms 3, 6, 12, 24 plotted as points (n, aₙ) lie on the exponential curve y = 1.5 · 2^x.Open in grapher →

The difference is only where the counting starts. The curve's initial value, 1.51.5, is the value that would come before the first term: a1÷r=3÷2a_1 \div r = 3 \div 2.

Working backward

If you know two terms but not the first term, use the fact that moving forward kk places multiplies by rkr^k.

Worked example: Two terms known

In a geometric sequence, a2=12a_2 = 12 and a5=324a_5 = 324. Find rr and a1a_1.

From a2a_2 to a5a_5 is 33 steps, so a5=a2⋅r3a_5 = a_2 \cdot r^3:

324=12r3⇒r3=27⇒r=3.324 = 12r^3 \quad\Rightarrow\quad r^3 = 27 \quad\Rightarrow\quad r = 3.

Then go back one step from a2a_2: a1=123=4a_1 = \dfrac{12}{3} = 4. Check: 4,12,36,108,3244, 12, 36, 108, 324.

Tip

Before using a formula, write out the first few terms from your rule and compare them with the given sequence. It catches off-by-one mistakes in the exponent right away.

Practice

Practice 1

What is the common ratio of the geometric sequence 3,12,48,192,…3, 12, 48, 192, \dots?

Enter a number. Fractions like 3/4 and sqrt(2) are OK.

Practice 2

What is the next term of 80,40,20,…80, 40, 20, \dots?

Enter a number. Fractions like 3/4 and sqrt(2) are OK.

Practice 3

Which sequence is geometric?

Practice 4

A geometric sequence has a1=2a_1 = 2 and r=3r = 3. Find a6a_6.

Enter a number. Fractions like 3/4 and sqrt(2) are OK.

Practice 5

Which is an explicit rule for 7,14,28,56,…7, 14, 28, 56, \dots?

Practice 6

Find the 77th term of 5,−10,20,−40,…5, -10, 20, -40, \dots

Enter a number. Fractions like 3/4 and sqrt(2) are OK.

Practice 7

A geometric sequence has a1=64a_1 = 64 and r=12r = \tfrac{1}{2}. Find a8a_8.

Enter a number. Fractions like 3/4 and sqrt(2) are OK.

Practice 8

In a geometric sequence with a positive ratio, a2=6a_2 = 6 and a5=162a_5 = 162. Find a1a_1.

Enter a number. Fractions like 3/4 and sqrt(2) are OK.