Math Core

Lesson 3.2 · Solving Inequalities

Solving one- and two-step inequalities

You already know how to solve equations by undoing operations until the variable stands alone. Inequalities are solved almost the same way, with one important twist. Once you know when that twist happens, you can solve any one- or two-step inequality and graph its solutions.

What stays the same

An inequality is like a scale that is tipped to one side. If you add the same weight to both pans, or take the same weight away, the scale stays tipped the same way. Numbers behave like that too.

Start with a true statement, 3<83 < 8:

  • Add 55 to both sides: 8<138 < 13. Still true.
  • Subtract 1010 from both sides: −7<−2-7 < -2. Still true.
  • Multiply both sides by 22: 6<166 < 16. Still true.
  • Divide both sides by 44: 0.75<20.75 < 2. Still true.

So adding, subtracting, and multiplying or dividing by a positive number all keep the inequality symbol exactly as it is.

What changes: multiplying by a negative

Now multiply both sides of 3<83 < 8 by −1-1. You get −3-3 and −8-8. But −3-3 is to the right of −8-8 on the number line, so −3>−8-3 > -8. The original symbol << would give a false statement; the true one is >>.

−10−8−6−4−20246810
Multiplying by −1 reflects each point across 0, so the order of the two numbers reverses.

Multiplying by a negative number reflects every number across 00. The number that used to be farther right ends up farther left, so the order reverses. Dividing by a negative does the same thing, since dividing by −4-4 is the same as multiplying by −14-\dfrac{1}{4}.

Properties of inequality

  • You may add or subtract the same number on both sides. The symbol stays the same.
  • You may multiply or divide both sides by the same positive number. The symbol stays the same.
  • If you multiply or divide both sides by a negative number, you must reverse the symbol: << becomes >>, ≤\le becomes ≥\ge, and so on.

One-step inequalities

Worked example: Adding, subtracting, multiplying, dividing

Solve each inequality and graph the solutions.

  1. x+7>12x + 7 > 12
  2. m4≤−2\dfrac{m}{4} \le -2
  3. −5y≥30-5y \ge 30

Solutions.

  1. Subtract 77 from both sides: x>5x > 5. Open circle at 55, shade right.
012345678910
  1. Multiply both sides by 44, a positive number, so the symbol stays: m≤−8m \le -8. Closed circle at −8-8, shade left.
−12−11−10−9−8−7−6−5−4−3−2
  1. Divide both sides by −5-5. The divisor is negative, so reverse the symbol:
−5y−5≤30−5⟹y≤−6.\frac{-5y}{-5} \le \frac{30}{-5} \quad\Longrightarrow\quad y \le -6.

Check a value from the answer: y=−7y = -7 gives −5(−7)=35-5(-7) = 35, and 35≥3035 \ge 30 is true. Check a value outside it: y=0y = 0 gives 0≥300 \ge 30, false. The flipped answer is right.

−10−9−8−7−6−5−4−3−2−10

Common mistake

Reverse the symbol only when you multiply or divide by a negative number. A negative number somewhere in the problem is not a reason to flip. In 3x<−123x < -12 you divide by positive 33, so the answer is x<−4x < -4 with no flip. In x−6>−2x - 6 > -2 you add 66, so the answer is x>4x > 4, again with no flip.

Two-step inequalities

Two-step inequalities are solved in the same order as two-step equations: undo addition or subtraction first, then undo multiplication or division.

Worked example: A two-step inequality

Solve 3x−5≥163x - 5 \ge 16.

3x−5≥163x≥21add 5x≥7divide by 3 (positive, no flip)\begin{aligned} 3x - 5 &\ge 16 \\ 3x &\ge 21 && \text{add } 5 \\ x &\ge 7 && \text{divide by } 3 \text{ (positive, no flip)} \end{aligned}

The solutions are all numbers 77 or greater.

Worked example: A negative coefficient

Solve 9−2x>159 - 2x > 15 and graph the solutions.

9−2x>15−2x>6subtract 9x<−3divide by −2 and reverse\begin{aligned} 9 - 2x &> 15 \\ -2x &> 6 && \text{subtract } 9 \\ x &< -3 && \text{divide by } -2 \text{ and reverse} \end{aligned}
−8−7−6−5−4−3−2−1012
x < -3

Check. The boundary x=−3x = -3 should make the two sides equal: 9−2(−3)=159 - 2(-3) = 15. Good. A number in the shaded part, x=−4x = -4, should make it true: 9−2(−4)=17>159 - 2(-4) = 17 > 15. Good.

Tip

Check every answer with two numbers. The boundary should make both sides equal, which confirms the number. A test point on the shaded side should make the original inequality true, which confirms the direction. A forgotten flip is caught instantly by the test point.

Inequalities in word problems

Word problems lead to inequalities whenever a limit is involved: a budget, a capacity, a minimum score.

Worked example: Staying under budget

A ride-share costs $4 to start plus $1.50 per mile. You have $25. How many miles can you ride?

Let dd be the number of miles. The total cost must be at most $25:

4+1.5d≤251.5d≤21subtract 4d≤14divide by 1.5\begin{aligned} 4 + 1.5d &\le 25 \\ 1.5d &\le 21 && \text{subtract } 4 \\ d &\le 14 && \text{divide by } 1.5 \end{aligned}

You can ride at most 1414 miles. Check: 4+1.5(14)=4+21=254 + 1.5(14) = 4 + 21 = 25, exactly your budget.

Notice the steps are the same as for an equation. The inequality just keeps track of the fact that anything less than 1414 miles is fine too.

Practice

Practice 1

Solve x−4<9x - 4 < 9.

Enter an inequality, e.g. x >= 4, -2 < x <= 3, or x < 1 or x > 5

Practice 2

Solve 6n≥−246n \ge -24.

Enter an inequality, e.g. x >= 4, -2 < x <= 3, or x < 1 or x > 5

Practice 3

Solve k−3<4\dfrac{k}{-3} < 4.

Enter an inequality, e.g. x >= 4, -2 < x <= 3, or x < 1 or x > 5

Practice 4

Solve 4x+3≤274x + 3 \le 27.

Enter an inequality, e.g. x >= 4, -2 < x <= 3, or x < 1 or x > 5

Practice 5

Solve 5−7x>195 - 7x > 19.

Enter an inequality, e.g. x >= 4, -2 < x <= 3, or x < 1 or x > 5

Practice 6

Which graph shows the solutions of x2+1≥−1\dfrac{x}{2} + 1 \ge -1?

Practice 7

Solve −2x−8≤2-2x - 8 \le 2.

Enter an inequality, e.g. x >= 4, -2 < x <= 3, or x < 1 or x > 5

Practice 8

A gym charges a $30 sign-up fee plus $12 per class. Maria wants to spend no more than $250. What is the greatest number of classes she can take?

Enter a number. Fractions like 3/4 and sqrt(2) are OK.