Lesson 5.3 · Equations and Inequalities
Two-step inequalities
A school club has $40 to spend on T-shirts. The club doesn't need to spend exactly $40. It just can't spend more. Questions like "how many can we afford?" lead to inequalities, and you can solve them almost exactly like two-step equations. There's just one new rule to learn.
Solving works (almost) like equations
You can add or subtract the same number on both sides of an inequality, and it stays true. You can also multiply or divide both sides by the same positive number.
Worked example: A familiar-looking inequality
Solve and graph the solutions.
Use the same steps as for : subtract , then divide by .
Every number greater than is a solution. The open circle shows that itself is not included.
Check: try a number in the shaded part, like : , and . ✓ Try one outside, like : , and is false. ✓
The one new rule: negatives flip the sign
Start with a true statement: . Now multiply both sides by . You get and . On a number line, is to the right of , so
The numbers switched places when they became negative, so the inequality symbol had to turn around to stay true.
Flip the symbol for negatives
When you multiply or divide both sides of an inequality by a negative number, reverse the inequality symbol.
becomes , becomes , becomes , and becomes .
Adding or subtracting a negative number does not flip the symbol.
Worked example: Dividing by a negative
Solve and graph the solutions.
The closed dot shows that is included.
Check: try : , and . ✓ Try , which is outside the shading: , and is false. ✓
Worked example: A negative fraction
Solve .
Subtract from both sides. The term is , so multiply both sides by and flip the symbol.
Check: try : , and . ✓
Common mistake
Forgetting to flip is the most common mistake. In , dividing by without flipping gives . Test : , and is false. So can't be right. Always test one number from your answer in the original inequality.
Word problems with inequalities
Watch for phrases like "at most," "no more than," "at least" and "a minimum of." After solving, think about what the solutions mean in the story.
Worked example: Buying T-shirts
The club has $40. T-shirts cost $12 each, plus a single $4 shipping charge. How many shirts can the club buy?
Let be the number of shirts. The total cost can be at most dollars:
The math says . But you can't buy shirts or shirt. So the club can buy , , or shirts, and 3 shirts is the most. Check: shirts cost dollars, which is allowed. shirts would cost dollars, which is too much.
Tip
To decide between an open circle and a closed dot, look at the symbol. and leave the endpoint out (open circle). and include it (closed dot).
Practice
Solve .
Enter an inequality, e.g. x >= 4, -2 < x <= 3, or x < 1 or x > 5
Solve .
Enter an inequality, e.g. x >= 4, -2 < x <= 3, or x < 1 or x > 5
Solve .
Enter an inequality, e.g. x >= 4, -2 < x <= 3, or x < 1 or x > 5
Solve .
Enter an inequality, e.g. x >= 4, -2 < x <= 3, or x < 1 or x > 5
Which inequality has the solutions shown on the number line?
Solve .
Enter an inequality, e.g. x >= 4, -2 < x <= 3, or x < 1 or x > 5
The drama club already has $50. It sells cookies for $2 each. It needs at least $200 for new costumes. What is the fewest number of cookies the club must sell?
Enter a number. Fractions like 3/4 and sqrt(2) are OK.
An elevator can carry at most pounds. The operator weighs pounds. Each box weighs pounds. What is the greatest number of boxes the operator can bring on one trip?
Enter a number. Fractions like 3/4 and sqrt(2) are OK.