Math Core

Lesson 6.3 · Transformations

Rotations

A Ferris wheel car, the hands of a clock and a spinning fan blade all move the same way: they turn around a fixed center. In geometry, that turn is called a rotation. On the coordinate plane, rotations around the origin follow a few neat coordinate rules.

What a rotation is

Definition

Rotation

A rotation turns every point of a figure through the same angle around a fixed point called the center of rotation. Each point stays the same distance from the center.

To describe a rotation, you need three things: the center, the angle, and the direction. Unless a problem says otherwise, a rotation is counterclockwise (the opposite way a clock's hands move). In this lesson, the center is always the origin, (0,0)(0, 0).

The coordinate rules

When you rotate a point 90∘90^\circ, its coordinates swap places and one of them changes sign. When you rotate 180∘180^\circ, both coordinates change sign.

Rotations about the origin

rotationruleexample with (4,1)(4, 1)
90∘90^\circ counterclockwise(x,y)→(−y,x)(x, y) \rightarrow (-y, x)(−1,4)(-1, 4)
180∘180^\circ(x,y)→(−x,−y)(x, y) \rightarrow (-x, -y)(−4,−1)(-4, -1)
90∘90^\circ clockwise(x,y)→(y,−x)(x, y) \rightarrow (y, -x)(1,−4)(1, -4)

A 90∘90^\circ clockwise turn ends in the same place as a 270∘270^\circ counterclockwise turn. And a 180∘180^\circ turn lands in the same spot whichever way you go.

Worked example: A quarter turn counterclockwise

Rotate triangle ABCABC with A(1,1)A(1, 1), B(4,1)B(4, 1) and C(4,3)C(4, 3) 90∘90^\circ counterclockwise about the origin.

Use (x,y)→(−y,x)(x, y) \rightarrow (-y, x): the new x-coordinate is the opposite of the old y, and the new y-coordinate is the old x.

A(1,1)→A′(−1,1)B(4,1)→B′(−1,4)C(4,3)→C′(−3,4)\begin{aligned} A(1, 1) &\rightarrow A'(-1, 1) \\ B(4, 1) &\rightarrow B'(-1, 4) \\ C(4, 3) &\rightarrow C'(-3, 4) \end{aligned}
Triangle ABC rotated 90° counterclockwise about the origin.Open in grapher →

The triangle started in Quadrant I and a quarter turn counterclockwise carried it into Quadrant II. Side ABAB was horizontal, and A′B′A'B' is vertical.

Worked example: A half turn

Rotate triangle ABCABC with A(2,1)A(2, 1), B(5,2)B(5, 2) and C(3,4)C(3, 4) 180∘180^\circ about the origin.

Use (x,y)→(−x,−y)(x, y) \rightarrow (-x, -y): A′(−2,−1)A'(-2, -1), B′(−5,−2)B'(-5, -2) and C′(−3,−4)C'(-3, -4).

Triangle ABC rotated 180° about the origin.Open in grapher →

The image is in the opposite quadrant. It looks upside down, but it has not been flipped over like a reflection.

Worked example: Clockwise

Rotate the point P(−3,5)P(-3, 5) 90∘90^\circ clockwise about the origin.

Use (x,y)→(y,−x)(x, y) \rightarrow (y, -x). The new x-coordinate is the old y, which is 55. The new y-coordinate is the opposite of the old x, which is −(−3)=3-(-3) = 3. So P′=(5,3)P' = (5, 3).

Check with quadrants: PP is in Quadrant II. A quarter turn clockwise moves Quadrant II to Quadrant I, and (5,3)(5, 3) is in Quadrant I. ✓

Common mistake

The 90∘90^\circ rules are easy to mix up. After you swap the coordinates, make sure you negate the right one. A quick check: a 90∘90^\circ counterclockwise turn moves Quadrant I → II → III → IV → I, and a clockwise turn goes the other way. If your answer lands in the wrong quadrant, you negated the wrong coordinate.

What stays the same

A rotation is a rigid motion. Lengths and angle measures stay the same, so the image is an exact copy. Unlike a reflection, a rotation also keeps orientation: if A→B→CA \to B \to C goes counterclockwise, so does A′→B′→C′A' \to B' \to C'.

Tip

If you can't remember a rule, turn your paper. Plot the point, rotate the whole page a quarter turn, and read where the point ended up against the axes.

Practice

Practice 1

Rotate the point (4,−7)(4, -7) 180∘180^\circ about the origin. What is the image?

Enter a point like (2, -3)

Practice 2

Rotate the point (2,5)(2, 5) 90∘90^\circ counterclockwise about the origin. What is the image?

Enter a point like (2, -3)

Practice 3

Rotate the point (2,5)(2, 5) 90∘90^\circ clockwise about the origin. What is the image?

Enter a point like (2, -3)

Practice 4

A 270∘270^\circ counterclockwise rotation about the origin gives the same image as which transformation?

Practice 5

Rotate the point (−6,−1)(-6, -1) 90∘90^\circ counterclockwise about the origin. What is the image?

Enter a point like (2, -3)

Triangle ABC and its image A′B′C′.Open in grapher →
Practice 6

Which rotation about the origin maps triangle ABCABC onto triangle A′B′C′A'B'C' in the graph above?

Practice 7

A point is rotated 90∘90^\circ counterclockwise about the origin, and its image is (−2,7)(-2, 7). What was the original point?

Enter a point like (2, -3)