Math Core

Lesson 6.3 · Inequalities

Solving two-step inequalities

Most real limits involve a starting amount plus a rate: a phone plan with a monthly fee plus a charge per gigabyte, or savings that grow by the same amount each week. Those situations give two-step inequalities. You solve them with the same plan you use for two-step equations, plus the flip rule from the last lesson.

The plan

Undo the operations in reverse order, just like with an equation:

  1. Add or subtract to get the variable term alone on one side.
  2. Multiply or divide to get the variable alone. If that number is negative, flip the symbol.
  3. Check a number from your answer in the original inequality, then graph.

Two steps, one possible flip

Solve a two-step inequality exactly like a two-step equation. The only difference comes in step 2: if you multiply or divide by a negative number, reverse the inequality symbol.

Worked example: No flip needed

Solve 5x−3≥175x - 3 \ge 17 and graph the solutions.

5x−3≥175x≥20(add 3)x≥4(divide by 5)\begin{aligned} 5x - 3 &\ge 17 \\ 5x &\ge 20 \qquad \text{(add } 3\text{)} \\ x &\ge 4 \qquad \text{(divide by } 5\text{)} \end{aligned}
012345678910
x ≥ 4

Check: try 66: 5(6)−3=275(6) - 3 = 27, and 27≥1727 \ge 17. ✓ Try 22, which is not shaded: 5(2)−3=75(2) - 3 = 7, and 7≥177 \ge 17 is false. ✓

Worked example: The variable term is negative

Solve 10−3x>110 - 3x > 1.

The xx term is −3x-3x. Subtract 1010 first, then divide by −3-3 and flip.

10−3x>1−3x>−9(subtract 10)x<3(divide by −3, flip)\begin{aligned} 10 - 3x &> 1 \\ -3x &> -9 \qquad \text{(subtract } 10\text{)} \\ x &< 3 \qquad \text{(divide by } -3\text{, flip)} \end{aligned}
−3−2−101234567
x < 3

Check: try 00: 10−0=1010 - 0 = 10, and 10>110 > 1. ✓ Try 44: 10−12=−210 - 12 = -2, and −2>1-2 > 1 is false. ✓

Common mistake

Watch out for 10−3x10 - 3x. The number in front of xx is −3-3, not 33, because the minus sign belongs to the 3x3x term. If you divide by 33 instead, you won't flip, and you'll get x>3x > 3. Test x=4x = 4 in the original: 10−12=−210 - 12 = -2, and −2>1-2 > 1 is false. So x>3x > 3 is wrong.

Worked example: A fraction

Solve x4+2≤−1\dfrac{x}{4} + 2 \le -1.

x4+2≤−1x4≤−3(subtract 2)x≤−12(multiply by 4)\begin{aligned} \dfrac{x}{4} + 2 &\le -1 \\ \dfrac{x}{4} &\le -3 \qquad \text{(subtract } 2\text{)} \\ x &\le -12 \qquad \text{(multiply by } 4\text{)} \end{aligned}

You multiplied by positive 44, so there's no flip, even though the answer is negative.

Check: try −16-16: −164+2=−4+2=−2\dfrac{-16}{4} + 2 = -4 + 2 = -2, and −2≤−1-2 \le -1. ✓

Parentheses: a preview of Algebra 1

Sometimes the inequality has parentheses, like 2(x+3)>142(x + 3) > 14. You can divide both sides by 22 first (it's positive, so no flip), or use the distributive property. Both work:

2(x+3)>14x+3>7(divide by 2)x>4\begin{aligned} 2(x + 3) &> 14 \\ x + 3 &> 7 \qquad \text{(divide by } 2\text{)} \\ x &> 4 \end{aligned}

Or: 2x+6>142x + 6 > 14, so 2x>82x > 8 and x>4x > 4. Same answer. In Algebra 1 you'll solve longer inequalities this way, with the variable on both sides.

Word problems

Translate the words into an inequality, solve it, and then ask what the answer means in the story. Often only whole numbers make sense.

Worked example: A phone plan

A phone plan costs $25 per month plus $4 for each gigabyte of data. Priya wants her bill to be no more than $45. How many gigabytes can she use?

Let gg be the number of gigabytes.

25+4g≤454g≤20g≤5\begin{aligned} 25 + 4g &\le 45 \\ 4g &\le 20 \\ g &\le 5 \end{aligned}

Priya can use at most 5 gigabytes. Check: 25+4(5)=4525 + 4(5) = 45, which is allowed. At 66 gigabytes, the bill is 4949 dollars, which is too much.

Tip

Use the story to double-check the direction. A budget ("no more than") should give a maximum, so expect ≤\le. A goal ("at least") should give a minimum, so expect ≥\ge.

Practice

Practice 1

Solve 3x+5<203x + 5 < 20.

Enter an inequality, e.g. x >= 4, -2 < x <= 3, or x < 1 or x > 5

Practice 2

Solve 2x−7≥−12x - 7 \ge -1.

Enter an inequality, e.g. x >= 4, -2 < x <= 3, or x < 1 or x > 5

Practice 3

Solve −4x+1>13-4x + 1 > 13.

Enter an inequality, e.g. x >= 4, -2 < x <= 3, or x < 1 or x > 5

Practice 4

Solve x5−2≤1\dfrac{x}{5} - 2 \le 1.

Enter an inequality, e.g. x >= 4, -2 < x <= 3, or x < 1 or x > 5

Practice 5

Solve 6−x3<86 - \dfrac{x}{3} < 8.

Enter an inequality, e.g. x >= 4, -2 < x <= 3, or x < 1 or x > 5

Practice 6

Solve 3(x−2)≥93(x - 2) \ge 9.

Enter an inequality, e.g. x >= 4, -2 < x <= 3, or x < 1 or x > 5

Practice 7

Which graph shows the solutions of 7−2x≤17 - 2x \le 1?

Practice 8

A gym charges a $30 sign-up fee plus $15 per month. Marcus can spend at most $150. What is the greatest number of months he can pay for?

Enter a number. Fractions like 3/4 and sqrt(2) are OK.

Practice 9

Lena has $18 saved. She earns $7 per hour walking dogs. She needs at least $95 for a new bike. What is the fewest whole number of hours she must work?

Enter a number. Fractions like 3/4 and sqrt(2) are OK.